If Sin =a^2-b^2\a^2+b^2 , find the …

CBSE, JEE, NEET, CUET
Question Bank, Mock Tests, Exam Papers
NCERT Solutions, Sample Papers, Notes, Videos
Posted by Rajat Arora 4 years, 11 months ago
- 2 answers
Gaurav Seth 4 years, 11 months ago

In ΔABC, Let ∠ABC be θ
Sin θ = (a2 - b2) / (a2 + b2)
⇒ AB = (a2 - b2)
⇒ AC = (a2 + b2)
⇒ BC = √[(a2 + b2)2 - (a2 - b2)2] [According to Pythagoras theorem]
⇒ BC = √(4a2b2)
⇒ BC = 2ab
Cos θ = 2ab / (a2 + b2)
Tan θ = (a2 - b2) / 2ab.
Cosec θ, Sec θ and Cot θ are the reciprocals of Sin θ, Cos θ, Tan θ respectively.
Related Questions
Posted by Vanshika Bhatnagar 1 year, 3 months ago
- 2 answers
Posted by Sahil Sahil 1 year, 3 months ago
- 2 answers
Posted by Kanika . 3 days, 2 hours ago
- 1 answers
Posted by Parinith Gowda Ms 2 months, 2 weeks ago
- 0 answers
Posted by Hari Anand 5 months, 1 week ago
- 0 answers
Posted by Parinith Gowda Ms 2 months, 2 weeks ago
- 1 answers

myCBSEguide
Trusted by 1 Crore+ Students

Test Generator
Create papers online. It's FREE.

CUET Mock Tests
75,000+ questions to practice only on myCBSEguide app
myCBSEguide
Rajat Arora 4 years, 11 months ago
0Thank You