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Sec3A=cosec(A-10) where 3A is an acute …

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Sec3A=cosec(A-10) where 3A is an acute angle so find the value of A

    • Posted by Bhoomika R 4 years, 9 months ago

    CBSE > Class 10 > Mathematics
    • 2 answers

    Neha Kumari 4 years, 9 months ago

    Sec3A=Cosec(A-10) Sec3A=Sec(100-A) 3A=100-A 4A=100 A=25.............(ans)

    1Thank You

    Aanya Jain 4 years, 9 months ago

    A is 25degree. sec(3A)=cosec (A-10) sec3A =sec(90-{A-10)} 3A=90+10-A 3A+A=100 4A=100 A=100/4 A=25

    2Thank You

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