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From the top of tower. 100 …

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From the top of tower. 100 m high, a man observes Two cars on the opposite sides of the tower with the angles of depression 3r & 4S" respectively, Find the distance between the cars

Posted by Anuj Ahire 4 years, 9 months ago

CBSE > Class 10 > Mathematics

1 answers

Gaurav Seth 4 years, 9 months ago

Let the Tower be AC = 100m
Distance between cars is BD
BD=BC+CD
Let the BC be 'x' and CD be 'y'

In Traingle ACD
Cot45°= Base/Perpendicular
Cot45°=y/100
1=y/100
y=100m

In Traingle ACB
Cot30°=x/100
1.732=x/100
1.732×100=x
x=173.2m

Distance between cars = BC+CD
=x+y
=173.2+100
=273.2m

0Thank You

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