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Represent 9.3 on number line...

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Represent 9.3 on number line...

    • Posted by P R 3 years, 10 months ago

    CBSE > Class 09 > Mathematics
    • 2 answers

    Sreevidhya Muralidharan 3 years, 10 months ago

    ANSWER Steps: 1) Draw a line segment AB of length 9.3 units. 2) Extend the line by 1 unit more such that BC=1 unit . 3) Find the midpoint of AC. 4) Draw a line BD perpendicular to AB and let it intersect the semicircle at point D. 5) Draw an arc DE such that BE=BD. Therefore, BE= Root 9.3 units

    0Thank You

    Gaurav Seth 3 years, 10 months ago

    <article id="post-1345619">
    1. Draw a line AB by measuring 9.3cm
    2. From the point, B add 1cm and mark it as C
    3. Mark the point of bisection by a compass and say it as ‘O’
    4. Measure AO which is the radius and draws a semi-circle.
    5. From B draw a perpendicular AB touching the semi-circle and mark as D
    6. Draw an arc on the number line by taking compass pointer on B and pencil on D
    7. The point which intersects the number line is the square root of 9.3
    </article>

    1Thank You

    ANSWER
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