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Prove that a diagonal of a …

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Prove that a diagonal of a parallelogram divides it into congruent triangle theorm
  • 1 answers

Gaurav Seth 3 years, 10 months ago

Given: A parallelogram ABCD and AC is its diagonal .

To prove : △ABC ≅ △CDA

Proof : In △ABC and △CDA, we have 

∠DAC =  ∠BCA [alt. int. angles, since AD | | BC] 

AC = AC [common side] 

and ∠BAC =  ∠DAC [alt. int. angles, since AB | | DC]  

∴ By ASA congruence axiom, we have 

△ABC ≅ △CDA

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