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.A force F is acting on …

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.A force F is acting on an object given by F=(3i^+4j^-6k^) N and displacement made by it is given by r=(6i^-2j^-k^) calculate the work done and power if work done is in 2s.
  • 1 answers

Rashmi Ahuja 3 years, 11 months ago

Work=F.d=(3i+4j-6k).(6i-2j-k) = (3×6)+(4×-2)+(-6×-1) = 18+(-8)+6= 16J Power=work÷time =16÷2 =8 watt
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