Find three numbers in G.P. whose …
CBSE, JEE, NEET, CUET
Question Bank, Mock Tests, Exam Papers
NCERT Solutions, Sample Papers, Notes, Videos
Posted by Dhruv Sharma 4 years, 3 months ago
- 2 answers
Yogita Ingle 4 years, 3 months ago
The three numbers in GP are 4 , 8 , 16.
- Let the three numbers in GP be a/r , a , ar.
- Now the product of three numbers is given as 512.
a/r × a × ar = 512
a³ = 512
a = 8
- Now sum of the three numbers is given as 28.
a/r + a + ar = 28
8/r + 8 + 8r = 28
8 + 8r² = 20r
8r² - 20r + 8 =0
8r² - 16r - 4r + 8 =0
8r(r-2) - 4(r-2) = 0
(r-2)(8r-4) = 0
- Therefore, r = 2 or r=1/2
- Now , the three numbers are 4,8,16.
Related Questions
Posted by Sabin Sultana 7 months, 2 weeks ago
- 0 answers
Posted by Manoj Thakur 7 months, 2 weeks ago
- 0 answers
Posted by Ananya Sv 7 months, 3 weeks ago
- 1 answers
Posted by Ashish Chaudhary 7 months, 2 weeks ago
- 1 answers
Posted by Sethpoulou Apoulou 7 months, 3 weeks ago
- 0 answers
Posted by Gurleen Kaur 7 months, 3 weeks ago
- 0 answers
Posted by Sana Dharwad 7 months, 2 weeks ago
- 0 answers
myCBSEguide
Trusted by 1 Crore+ Students
Test Generator
Create papers online. It's FREE.
CUET Mock Tests
75,000+ questions to practice only on myCBSEguide app
Ranger King 4 years, 3 months ago
1Thank You