Plzzzz someone tell me the value …

The Trigonometry Ratios of the angle θ in the triangle APM are defined as follows.

Opposite over Hypotenuse – Sin, Adjacent Over Hypotenuse – Cos, Opposite over Adjacent – Tan, Hypotenuse over Opposite – Cosec, Hypotenuse Over Adjacent – Sec and Adjacent over Opposite – Cotangent,

The ratios defined above are abbreviated as sin θ, cos θ, tan θ, cosec θ, sec θ and cot θ respectively. Note that the ratios cosec θ, sec θ and cot θ are respectively, the reciprocals of the ratios sin θ, cos θ and tan θ. So, the trigonometric ratios of an acute angle in a right triangle express the relationship between the angle and the length of its sides.

Opposite of Sin: Cosecant

Opposite of Cos: Secant

Opposite of Tan: Cotangent

Opposite of Cosecant: Sin

Opposite of Cotangent:  Tan

Opposite of Secant: Cosecant

Trig Mnemonics –  Some People Have, Curly Black Hair Through Proper Brushing.

Here, Some People Have is for

• Sin θ= Perpendicular/ Hypotenuse.

Curly Black Hair is for

• Cos θ= Base/ Hypotenuse.

Through Proper Brushing is for

• Tan θ= Perpendicular/Base

Trigonometric Ratios of Some Specific Angles

We already know about isosceles right angle triangle and right angle triangle with angles 30º, 60º and 90º.
Can we find sin 30º or tan 60º or cos 45º etc. with the help of these triangles?
Does sin 0º or cos 0º exist?

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