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Find the value of k for which the line (K +1)x + 3ky + 15 =0 and 5x + ky + 5 coincident

Posted by Shreya Chatterjee 4 years, 9 months ago

CBSE > Class 10 > Mathematics

1 answers

Gaurav Seth 4 years, 9 months ago

The given equations are:

(k+1)x+3ky+15=0, and

5x+ky+5=0

Since, the given equations are coincident, therefore

{tex}\frac{a_{1}}{a_{2}}=\frac{b_{1}}{b_{2}}=\frac{c_{1}}{c_{2}} \frac{k+1}{5}=\frac{3k}{k}=\frac{15}{5}{/tex}

Taking the first two terms, we have

k=14

The given equations are:

, and

Since, the given equations are coincident, therefore

Taking the first two terms, we have

2Thank You

ANSWER

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