An aeroplane flying at a height …
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Gaurav Seth 4 years, 9 months ago
Height of first Airplane = AB = 4000 m
Height of another plane = BC
The angles of elevation of two planes from the same point on the ground are 60° and 45°. i.e.∠ADB = 60° and ∠CDB = 45°
Let AC be h
CB = AB - AC = 4000-h
In ΔABD
In ΔCBD
Hence the vertical distance between the aeroplane at that instant is 1690.599 m
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