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An aeroplane flying at a height …

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An aeroplane flying at a height of 4000m from the ground vertically above another aeroplane at an instant when the angles of elevation of the two planes from the same point on the ground are 60°and 45° respectively. Find the vertical distance between the aeroplanes at that instant.

Posted by Gopika Satheesh 4 years, 11 months ago

CBSE > Class 10 > Mathematics

1 answers

Gaurav Seth 4 years, 11 months ago

Height of first Airplane = AB = 4000 m

Height of another plane = BC

The angles of elevation of two planes from the same point on the ground are 60° and 45°. i.e.∠ADB = 60° and ∠CDB = 45°

Let AC be h

CB = AB - AC = 4000-h

In ΔABD

In ΔCBD

Hence the vertical distance between the aeroplane at that instant is 1690.599 m

1Thank You

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