1. In the figure ,quad. ABCD …

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Yogita Ingle 5 years, 4 months ago
Tangents drawn from am external point to a circle
are equal in length
so from the diagram we get
AH= AE; DH = DG; CG=CF
4−x=x y=2y−3
2x=4 y=3
x=2
As x=2 DH = 5 − AH = 5−(4−x) =3
as DH=DG DG=3
So Length of CD=CG+GD
=3+3=6
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