Dimensional formula of self induction
CBSE, JEE, NEET, CUET
Question Bank, Mock Tests, Exam Papers
NCERT Solutions, Sample Papers, Notes, Videos
Posted by Priya Kumari 4 years, 5 months ago
- 1 answers
Related Questions
Posted by M D 9 months, 2 weeks ago
- 1 answers
Posted by Pankaj Tripathi 9 months, 3 weeks ago
- 1 answers
Posted by Nekita Baraily 9 months, 3 weeks ago
- 2 answers
Posted by Mansi Class 9Th 9 months, 3 weeks ago
- 0 answers
Posted by Mohammed Javith 10 months ago
- 0 answers
myCBSEguide
Trusted by 1 Crore+ Students
Test Generator
Create papers online. It's FREE.
CUET Mock Tests
75,000+ questions to practice only on myCBSEguide app
Yogita Ingle 4 years, 5 months ago
The magnetic flux is given by
ϕ=LI
The dimensional formula of self inductance, [L]=[BA]/[I]. . . . . .(1)
Force, f=qvB
[M1L1T−2]=[TA].[L1T−1].[B]
[B]=[M1T−2A−1]
[BA]=[M1L2T−2A−1]
From equation (1), we get
[ϕ]=[M1L2T−2A−2]
1Thank You