in triangle abc ,angle b =90°d …
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Yogita Ingle 3 years, 10 months ago
In ∆ABC , angle B=90° and D is a point on hypotenuse AC such that angle DBC
= angle DCB.
In,∆ABC. let angle ACB or DCB = x° , then angle BAC or BAD = 90°-x………..(1)
In. ∆ DBC angle DBC= angle DCB=x°………..(given)
But angle ABD+angle DBC =90°
or. angle ABD. = 90°-x°……………(2)
from eqn. (1) and (2)
angle BAD =angle ABD…….(In ∆ DAB opposite angles are equal ,then opposite
sides are also equal.)
Thus , side BD = side AD. Proved.
1Thank You