find the area of the quadrilateral …
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Posted by Cbz Hero 3 years, 10 months ago
- 2 answers
Gaurav Seth 3 years, 10 months ago
Step-by-step explanation:
in triangle BCD,
semiperimeter (s) = BC + CD + BD/2
s = 60 + 30 + 70 /2
s = 160/2
s = 80
a = root[80 x (80-60) (80-30) (80 - 70)]
a = root[80 x 20 x 50 x 10]
a = root[ 10 x 4 x 2 x 2 x 10 x 5 x 10 x 10]
a = 10 x 4 x 10 root(5)
a = 400xroot(5)
a = 894.4 (approx)
In triangle ABD,
semiperimeter (s) = AB + BD + DA/2
s = 50 + 70 + 90/2
s = 210/2
s = 105
a = root[105 x (105- 50) (105-90) (105 - 70)]
a = root[105 x 55 x 15 x 35]
a = root[ 5 x 7 x 3 x 5 x 11 x 5 x 3 x 7 x 5]
a = 25 x 7 x 3 root(11)
a = 525 * root(11)
a = 1741.2 (approx)
Total area = 894.4 + 1741.2
= 2635.6 cm2(approx
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Cbz Hero 3 years, 10 months ago
1Thank You