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When 150 g of ice at …

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When 150 g of ice at 0°C is mixed with 300 g of the water at 50°C in a container. Find the resulting temperature. (Specific heat of water = 1cal/gm/°C, Latent heat of ice = 80cal/gm.)
  • 1 answers

Yogita Ingle 3 years, 11 months ago

Let us assume that T>0
Heat lost by water= heat gained by ice to melt+ heat gained by water formed from ice
⇒300×1×(50−T)=150×80+150×1×(T−0) 
⇒T=6.7C
⇒T=6.7C
Hence our assumption that T>0C  

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