Solve the following equation. Check your …

2(?−2)+3(4?−1)=0 2(x-2)+3(4x-1)=02(x−2)+3(4x−1)=0 Solve 1 Distribute 2(?−2)+3(4?−1)=0 {\color{#c92786}{2(x-2)}}+3(4x-1)=02(x−2)+3(4x−1)=0 2?−4+3(4?−1)=0 {\color{#c92786}{2x-4}}+3(4x-1)=02x−4+3(4x−1)=0 2 Distribute 2?−4+3(4?−1)=0 2x-4+{\color{#c92786}{3(4x-1)}}=02x−4+3(4x−1)=0 2?−4+12?−3=0 2x-4+{\color{#c92786}{12x-3}}=02x−4+12x−3=0 3 Subtract the numbers 2?−4+12?−3=0 2x{\color{#c92786}{-4}}+12x{\color{#c92786}{-3}}=02x−4+12x−3=0 2?−7+12?=0 2x{\color{#c92786}{-7}}+12x=02x−7+12x=0 4 Combine like terms 2?−7+12?=0 {\color{#c92786}{2x}}-7+{\color{#c92786}{12x}}=02x−7+12x=0 14?−7=0 {\color{#c92786}{14x}}-7=014x−7=0 5 Add  7 77  to both sides of the equation 14?−7=0 14x-7=014x−7=0 14?−7+7=0+7 14x-7+{\color{#c92786}{7}}=0+{\color{#c92786}{7}}14x−7+7=0+7 6 Simplify Add the numbers Add the numbers 14?=7 14x=714x=7 7 Divide both sides of the equation by the same term 14?=7 14x=714x=7 14?14=714 \frac{14x}{{\color{#c92786}{14}}}=\frac{7}{{\color{#c92786}{14}}}1414x​=147​ 8 Simplify Cancel terms that are in both the numerator and denominator Divide the numbers ?=12 Solution=½

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