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Decomposition of a compound follows first …

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Decomposition of a compound follows first order kinetics. If it takes 15 minutes for 20% or original substance to decay.calculate 1. Rate constant 2. The time at which 10% of the reactant remains undecayed

    • Posted by Ngamthuipou Malangmei 3 years, 11 months ago

    CBSE > Class 12 > Chemistry
    • 1 answers

    Abhi Panday 3 years, 11 months ago

    By using first order eq :kt=2.303 log (a/a-a') 20 percent is reduced than 80 percent left K=2.303 log (a/.80a) /15 K=2.303log(100/80) /15 K=2.303log (5/4) /15 K=2.303*.09/15 K=0.207/15 K=0.0138(1/s) 2) t=2.303 log (a/.10a) /.015 t=2.303 log(100/10) /.015 t=2.303*1/.015 t=153.5 min 3) first reduce 20 percent in 15 min after reduceing 80 percent left than 20 percent is more reduce from 80 percent than than 16 percent is remove from 80 percent t=2.303 log (.80a/.80a-.16a) /.015 t=2.303 log 1.25 /.015 t=153.4*log 1.25 t=153.4*.09 t=14.56 min

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