No products in the cart.

5. In figure, ABC and BDF …

CBSE, JEE, NEET, CUET

CBSE, JEE, NEET, CUET

Question Bank, Mock Tests, Exam Papers

NCERT Solutions, Sample Papers, Notes, Videos

5. In figure, ABC and BDF are two equilateral triangles such that D is the mid-point of BC. If AE intersects BC at F, show that: (i) ar (BDE) = ar (ABC) (ii) ar (BDE) = ar (BAE) (iii) ar (ABC) = 2 ar (BEC) (iv) ar (BFE) = ar (AFD) (v) ar (BFE) = 2 ar (FED) (vi) ar (FED) = ar (AFC)
  • 1 answers

Devi Lal 3 years, 10 months ago

Jsbdiwbdjzbsjabsksxxvd
http://mycbseguide.com/examin8/

Related Questions

X³-12x²+39x-28
  • 0 answers
Ch-1 introduction
  • 0 answers
2x+5y
  • 0 answers
What is 38747484±393884747
  • 0 answers
3√2×4√2×12√32
  • 0 answers

myCBSEguide App

myCBSEguide

Trusted by 1 Crore+ Students

Test Generator

Test Generator

Create papers online. It's FREE.

CUET Mock Tests

CUET Mock Tests

75,000+ questions to practice only on myCBSEguide app

Download myCBSEguide App