5. In figure, ABC and BDF …
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5. In figure, ABC and BDF are two equilateral triangles such that D is the mid-point of BC. If AE intersects BC at F, show that:
(i) ar (BDE) = ar (ABC)
(ii) ar (BDE) = ar (BAE)
(iii) ar (ABC) = 2 ar (BEC)
(iv) ar (BFE) = ar (AFD)
(v) ar (BFE) = 2 ar (FED)
(vi) ar (FED) = ar (AFC)
Posted by Vyshnavi R 3 years, 10 months ago
- 1 answers
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Devi Lal 3 years, 10 months ago
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