From the top of a lighthouse …

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From the top of a lighthouse the angles of depression of two ships on the opposite side of it are observed to be alpha and beta. If the height of the lighthouse be h meters and the line joining the ships passes through the foot of the lighthouse show that the distance between the ship is h(tan alpha + tan beta) /tan alpha tan beta meters
Posted by Gopika Satheesh 4 years, 11 months ago
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Gaurav Seth 4 years, 11 months ago
Let AD be the lighthouse whose height is h metres. 13 and C are the position of two ships which are on opposite sides of lighthouse. The angles of depression of two ships B and C from the top of the lighthouse are α and β respectively.

i.e., ∠ABD = α and ∠ACD = β



metres.
Let BD = x m and CD = y m
In right triangle ABD, we jave
In right triangle ACD, we have
Adding (i) and (ii), we get
Hence, the distance between the ship is
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