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Three vertices of a parallelogram taken …

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Three vertices of a parallelogram taken in order are (0,3) (0,6) and (2,9). Find the fourth vertex.
  • 3 answers

Нαяѕнιтα 🖤 4 years, 9 months ago

2,6

Siddhi Bhandari 4 years, 9 months ago

Let A(- 1, 0), B(3, 1),  C(2, 2) and D(x, y) be the vertices of a parallelogram ABCD taken in order.  Since, the diagonals of a parallelogram bisect each other. So, coordinate of the mid point of AC = coordinate of mid point of BD ⇒ [(-1 + 2)/2, (0 + 2)/2] = [(3 + x)/2, (y + 1)/2] ⇒ (1/2, 1) = [(3 + x)/2, (y + 1)/2] (3 + x)/2 = ½ ⇒  x = - 2 Also  (y + 1)/2 = 1 ⇒ y + 1 = 2 ⇒ y = 1 The fourth vertex of parallelogram = (- 2, 1).

Avni Soni 4 years, 9 months ago

(2,6)
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