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If k+1,3,4k+2 be any three consecutive …

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If k+1,3,4k+2 be any three consecutive terms of an AP find the value of k?
  • 2 answers

Ajay Kumar 4 years, 9 months ago

K=3/5 hoga

Yogita Ingle 4 years, 9 months ago

1st term t1 = (k + 1).
2nd term t2 = 3k.
3rd term t3 = (4k + 2).
Given that t1,t2,t3 are in AP.
We know that when they are in AP, their common difference will be:
t2 - t1 = t3 - t2
3k - (k + 1) = (4k + 2) - 3k
3k - k - 1 = 4k + 2 - 3k
2k - 1 = k + 2
2k = k + 2 + 1
2k = k + 3
2k - k = 3
k = 3.
Therefore the value of k = 3.

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