(b) using suitable identities calculate value …
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Posted by Arun Kushwah 3 years, 11 months ago
- 1 answers
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Yogita Ingle 3 years, 11 months ago
We have,
(99)3 =(100−1)3
We know that
(a−b)3=a3−b3−3ab(a−b)
Therefore,
=(100)3−13−3×100×1×(100−1)
=1000000−1−300(100−1)
=1000000−1−30000+300
=970299
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