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(b) using suitable identities calculate value of (99)³ . Only this much. Thanks you.....

Posted by Arun Kushwah 5 years, 1 month ago

CBSE > Class 09 > Mathematics

1 answers

Yogita Ingle 5 years, 1 month ago

We have,

(99)³=(100−1)³

We know that

(a−b)³=a³−b³−3ab(a−b)

Therefore,

=(100)³−1³−3×100×1×(100−1)

=1000000−1−300(100−1)

=1000000−1−30000+300

=970299

1Thank You

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