Prove thata the tangent drawn at …

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Posted by Vedika Roongta 5 years ago
- 2 answers
Yogita Ingle 5 years ago
Given:- A circle with center O,PA and PB are tangents drawn at ends A and B on chord AB.
To prove:- ∠PAB=∠PBA
Construction:- Join OA and OB
Proof:- In △AOB, we have
OA=OB(Radii of the same circle)
∠OAB=∠OBA.....(1)(Angles opposite to equal sides)
∠OAP=∠OBP=90(∵Radius⊥Tangent)
⇒∠OAB+∠PAB=∠OBA+∠PBA
⇒∠OAB+∠PAB=∠OAB+∠PBA(From (1))
⇒∠PAB=∠PBA
Hence proved.

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Raja Gupta 5 years ago
0Thank You