Prove thata the tangent drawn at …
CBSE, JEE, NEET, CUET
Question Bank, Mock Tests, Exam Papers
NCERT Solutions, Sample Papers, Notes, Videos
Posted by Vedika Roongta 4 years, 9 months ago
- 2 answers
Yogita Ingle 4 years, 9 months ago
Given:- A circle with center O,PA and PB are tangents drawn at ends A and B on chord AB.
To prove:- ∠PAB=∠PBA
Construction:- Join OA and OB
Proof:- In △AOB, we have
OA=OB(Radii of the same circle)
∠OAB=∠OBA.....(1)(Angles opposite to equal sides)
∠OAP=∠OBP=90(∵Radius⊥Tangent)
⇒∠OAB+∠PAB=∠OBA+∠PBA
⇒∠OAB+∠PAB=∠OAB+∠PBA(From (1))
⇒∠PAB=∠PBA
Hence proved.
Related Questions
Posted by Kanika . 1 month ago
- 1 answers
Posted by Hari Anand 3 months ago
- 0 answers
Posted by Sahil Sahil 1 year, 1 month ago
- 2 answers
Posted by Parinith Gowda Ms 1 week, 3 days ago
- 1 answers
Posted by Vanshika Bhatnagar 1 year, 1 month ago
- 2 answers
Posted by Parinith Gowda Ms 1 week, 3 days ago
- 0 answers
Posted by Lakshay Kumar 9 months, 3 weeks ago
- 0 answers
myCBSEguide
Trusted by 1 Crore+ Students
Test Generator
Create papers online. It's FREE.
CUET Mock Tests
75,000+ questions to practice only on myCBSEguide app
Raja Gupta 4 years, 9 months ago
0Thank You