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A piece of wire of resistance 20 ohm is drawn out so its length is increased twice. Calculate the resistance of the wire

Posted by Francis Lalu 5 years, 1 month ago

CBSE > Class 10 > Science

1 answers

Yogita Ingle 5 years, 1 month ago

R=20 Ω

Let,Length of wire is L and when it drawn out, its new length is 2L

The volume of wire in both the situations remains constant.So, it the length of wire doubled, the area of cross section of wire becomes half.

So, the new resistance of wire-
R_new = 2l/(A/2)

=4LA

=4×Old resistance of wire (Because, R=L/A)

=4×20 = 80 Ω

1Thank You

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