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The perimeter of a rectangle is …

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The perimeter of a rectangle is a 80m .its length is 8 metre more than its breadth find its length and breadth.

    • Posted by Sakshi Komal 4 years, 11 months ago

    CBSE > Class 07 > Mathematics
    • 4 answers

    Devanshu Kumar 4 years, 11 months ago

    Let the breadth of the rectangle be x We are given that the length of a rectangle is 8 0m more than its breadth. So, the Lengthy of the rectangle is x+8 Perimeter of rectangle = 2(length + breadth)  2(x + x + 8) = 80 2x + 8 = 40 2x = 40 - 7 = 32 x = 32/2 = 16 We are given that perimeter is 80m So,  So, Breadth = 16 m Length = 16+8 = 24 m

    0Thank You

    Diksha Janghu 4 years, 11 months ago

    Breadth= d, Length=d+8 Perimeter=2(l+b), 2(d+d)=80m, 2d=80m, d=80/2, d=40, Breadth=40, Length=40+8=48

    1Thank You

    Gaurav Seth 4 years, 11 months ago

    given :-

    perimeter of the rectangle = 80m

    ATQ, length of the rectangle is one more meter than twice it's breadth.

    let the breadth of the rectangle be x

    therefore it's length will be = 2x + 1

    formula to find the perimeter of a rectangle is 2(l + b)

    so we can write,

    ➡ 2(l + b) = 80 meters

    putting value of b and l,

    ➡ 2(2x + 1 + x) = 80m

    ➡ 3x + 1 = 80/2

    ➡ 3x = 40 - 1

    ➡ x = 39/3

    ➡ x = 13m

    hence,

    breadth of the rectangle = x

    = 13m

    and length of the rectangle = 2x + 1

    = 2(13) + 1

    = 27m

    0Thank You

    Yogita Ingle 4 years, 11 months ago

    Let the breadth of the rectangle be x

    We are given that the length of a rectangle is 8 0m more than its breadth.

    So, the Lengthy of the rectangle is x+8

    Perimeter of rectangle = 2(length + breadth)

     2(x + x + 8) = 80

    2x + 8 = 40

    2x = 40 - 7 = 32

    x = 32/2 = 16

    We are given that perimeter is 80m

    So, 

    So, Breadth = 16 m

    Length = 16+8 = 24 m

    0Thank You

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