Represent√9.3 on the number line
CBSE, JEE, NEET, CUET
Question Bank, Mock Tests, Exam Papers
NCERT Solutions, Sample Papers, Notes, Videos
Posted by Poonam Singh 3 years, 11 months ago
- 1 answers
Related Questions
Posted by Akhilesh Patidar 2 months, 3 weeks ago
- 0 answers
Posted by Alvin Thomas 2 months, 3 weeks ago
- 0 answers
Posted by Savitha Savitha 2 months, 3 weeks ago
- 0 answers
Posted by T Prudhvi 22 hours ago
- 0 answers
Posted by Gnani Yogi 2 months, 3 weeks ago
- 0 answers
Posted by Sheikh Alfaz 4 days, 14 hours ago
- 0 answers
myCBSEguide
Trusted by 1 Crore+ Students
Test Generator
Create papers online. It's FREE.
CUET Mock Tests
75,000+ questions to practice only on myCBSEguide app
Gaurav Seth 3 years, 10 months ago
STEPS: 1: On a numberline mark AB = 9.3 unit & BC= 1 unit.
2: Mark O the mid point of AC
3: Draw a semicircle with O as centre & OA as radius
4: At B draw a perpendicular BD.
5: BD = √9.3 unit
6: Now, B as centre, BD as radius, draw an arc, meeting the numberline at E.
Now, with BD or BE = √9.3 as radius , with 0 ( origin) of the number line as centre, draw an arc on the the number line, intersecting at point ‘k’. And this point ‘k' lies between integers 3 & 4, & represents √9.3
JUSTIFICATION:
BD = √ {(10.3/2)² - (8.3/2)²}
=> BD = √{10.3²- 8.3²)/4 }
=> BD = √{(10.3+8.3)(10.3–8.3)/4}
=> BD = √{18.6*2/4}
=> BF = √{37.2/4}
=> BD = √9.3 = BE
0Thank You