Find The Perimeter of rectangle Whose …

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- 2 answers
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Yogita Ingle 5 years ago
Given diagonal (PR)=41cm, length (PQ)=40cm
Let breadth(QR) be x cm.
Now, in right angled triangle PQR,
(PR)2=(RQ)2+(PQ)2 [By Pythagoras theorem]
⇒(41)2=x2+(40)2
⇒1681=x2+1600
⇒x2=1681−1600
⇒x2=81
⇒x=81=9cm
Therefore the breadth of the rectangle is 9 cm.
Perimeter of rectangle=2(length+breadth)
=2(9+49)
=2×49=98cm
Hence the perimeter of the rectangle is 98cm.
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