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An electron moving with K.E 25keV …

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An electron moving with K.E 25keV moves perpendicular to a uniform Magnetic field of 0.2 mT . calculate the time period of rotation of electron in magnetic field.
  • 2 answers

Anushka Singh 4 years, 10 months ago

Thnxxx..

Gaurav Seth 4 years, 10 months ago

The time period is given as

T = 2πm / Bq

where

mass of the electron, m = 9.1 X 10-31 kg

magnetic field strength, B = 0.2 mT = 0.2 X10-3 T

charge on the electron, q = 1.6 X10-19 C

so,

T = (2 X3.14 X 9.1 X 10-31) / (0.2 X10-3 X 1.6 X10-19)

or

T = (57.148/0.32) X 10-9



thus, the time period will be

T = 1.785 X 10-7 secs.

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