) A passenger of mass 72.2 …
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Yogita Ingle 4 years ago
Given, mass, m = 72.2 kg
Gravity acceleration, g = 9.8 m/${{s}^{2}}$ Scale reading = apparent weight = R = ?
(i) While descending with constant velocity, a =0
R = mg
R = 72.2 x9.8
=>R = 707.56 N
(ii) While ascending with a = 3.2 m/${{s}^{2}}$
R = m(g + a)
R = 72.2 (9.8 + 3.2) = 938.6 N
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