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The refractive index of a meduim …

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The refractive index of a meduim x with respect to a meduim Y is 2/3 and reflactive index of meduim Y with respect to meduim z is 4/3 find the refeactive index of a meduim Z with respect to meduim X if the speed of light in meduim X is 3×10^8m/s . calculate the speed of light in meduim Y.

Posted by Rubi Kumari 5 years, 1 month ago

CBSE > Class 10 > Science

1 answers

Rubi Kumari 5 years, 1 month ago

nxy=2/3------eq1 nyz=4/3------eq2 nzx=? nzx=nxy×nyz =2/3×4/3 nxz=8/9 nzx=9/8 nxy=light of speed in meduim y/light of speed in meduim x 2/3=y/3×10^8 2/3×3×10^8 2×10^8 m/s

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