Refractive index in transparent medium

CBSE, JEE, NEET, CUET
Question Bank, Mock Tests, Exam Papers
NCERT Solutions, Sample Papers, Notes, Videos
Posted by Faisal Khan 5 years, 1 month ago
- 3 answers
Faisal Khan 5 years, 1 month ago
Yogita Ingle 5 years, 1 month ago
Refractive index of a transparent medium decreases with increase in wavelength of the incident light used.
Refractive index of glass with respect to air is given
μ=Speed of light in air/speed of light in glass =3×108 m/s/ 2×108 m/s=1.5
Now,
μ=1/siniC
⇒siniC= 1/μ
iC=sin−1(1/μ)=sin−1(1/1.5)=sin−1(2/3).
Related Questions
Posted by Harshal Patil 10 months, 1 week ago
- 0 answers
Posted by Rani Alan 1 year, 4 months ago
- 1 answers
Posted by Aadarsh Tripathi 1 year, 4 months ago
- 2 answers
Posted by Pandey Ji 5 months, 4 weeks ago
- 0 answers
Posted by Tushar Sharma 1 year, 4 months ago
- 2 answers
Posted by Harshita Tondey 1 year, 4 months ago
- 3 answers
Posted by Ansh Preet 10 months, 1 week ago
- 1 answers
Posted by Surya Kumar 1 year, 4 months ago
- 1 answers

myCBSEguide
Trusted by 1 Crore+ Students

Test Generator
Create papers online. It's FREE.

CUET Mock Tests
75,000+ questions to practice only on myCBSEguide app
myCBSEguide
Faisal Khan 5 years ago
0Thank You