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In a hot water heating system …

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In a hot water heating system there is a cylindrical pipe of length 28 m abs and diameter 5 cm . Find the total radiating surface in the system

    • Posted by Manika Sangal 5 years, 1 month ago

    CBSE > Class 09 > Mathematics
    • 2 answers

    Sunaada Acharya 5 years, 1 month ago

    Answer. Given length = 28 m. diameter = 5 cm then the radius will be r = 5/2 cm = 0.025m. = 4.4 m^2.

    2Thank You

    Gaurav Seth 5 years, 1 month ago

    Height of cylinder (h) = Length of cylindrical pipe = 28 m or 2800 cm [1 m = 100 cm]  Diameter of circular end of pipe = 5 cm Let ‘r’ be the radius of circular end, then  r = diameter/2 = 5/2 cm  We know,  Curved surface area of cylindrical pipe = 2πrh  = 2 x 3.14 x 5/2 x 2800 = 44000  Therefore, the area of radiating surface is 44000 cm2.

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