State Gauss’s law in electrostatics. Show …
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State Gauss’s law in electrostatics. Show that with help of suitable figure
that outward flux due to a point charge Q, in vacuum within gaussian
surface, is independent of its size and shape.
b) In the figure there are three infinite long thin sheets having surface
charge density +2σ, -2σ and +σ respectively. Give the magnitude and
direction of electric field at a point to the left of sheet of charge density
+2σ and to the right of sheet of charge density +σ.
Posted by Spurti . 4 years, 7 months ago
- 1 answers
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Yogita Ingle 4 years, 7 months ago
As per the Gauss theorem, the total charge enclosed in a closed surface is proportional to the total flux enclosed by the surface. Therefore, If ϕ is total flux and ϵ0 is electric constant, the total electric charge Q enclosed by the surface is; Q = ϕ ϵ0.
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