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Find the zeroes of the polynomial …

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Find the zeroes of the polynomial 6x²-7x-3 and verify the relationship between zeroes and coefficients of the polynomial

Posted by Janvi Rajput 5 years ago

CBSE > Class 10 > Mathematics

3 answers

King Adithya H M... 5 years ago

Let 6x2 - 7x- 3 be p(x) =0 so,6x2 - 7x-3 =0 6x2 - (9-2) x -3 6x2 - 9x + 2x -3 (6x2 - 9x)(2x-3) 3x(2x-3) +1 (2x-3) (3x +1) (2x -3) = 0 ⇒ 3x +1 = 0 ⇒ 2x -3 = 0 ⇒ x =3/2 ⇒ x = - 1/3 sum of zeroes = -1/3 + 3/2 =7/6 = -b/a product of zeroes =- 1/3 * 3/2 = - 3/6 or -1/2 = c/a

Archita Gupta 5 years ago

6x²- 7x-3 6x²+2x-9x-3 2x(3x+1)-3(3x+1) (2x-3) (3x+1) 2x-3=0 2x=3 X=3/2 3x+1=0 3x= -1 x=-1/3 Sum of zeroes =- coefficient x/coefficient of x² 3/2+(-1)/3=-(-7)/6 9-2/6 =7/6 7/6=7/6 Produce of zeroes = constant term / coefficient of x² 3/2×(-1)/3=(-3)/6 -3/6=-3/6

Gaurav Seth 5 years ago

Let 6x² - 7x- 3 be p(x) =0

so,6x²- 7x-3 =0

6x² - (9-2) x -3

6x²- 9x + 2x -3

(6x²- 9x)(2x-3)

3x(2x-3) +1 (2x-3)

(3x +1) (2x -3) = 0

⇒ 3x +1 = 0

⇒ 2x -3 = 0

⇒ x =3/2

⇒ x = - 1/3

sum of zeroes = -1/3 + 3/2 =7/6 = -b/a

product of zeroes =- 1/3 * 3/2 = - 3/6 or -1/2 = c/a

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