(2x-y+z)^2
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Yogita Ingle 3 years, 11 months ago
(a+b+c)2 = a2+b2+c2+2ab+2bc+2ca
⇒(2x−y+z)2=(2x)2+(−y)2+(z)2+2(2x×−y)+2(−y×z)+2(z×2x)
=4x2 + y2+z2−4xy−2yz+4xz
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