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how many three of digit natural numbers are divisible by 7

Posted by Krishnpal Yadav 5 years ago

CBSE > Class 10 > Mathematics

2 answers

Rohan Kumar 5 years ago

105, 112, 119, ..., 994 This is an AP with first term (a) = 105 and common difference (d) = 7 Let an be the last term. an = a + (n - 1)d 994 = 105 + (n - 1)(7) 7(n - 1) = 889 n - 1 = 127 n = 128 Thus, there are 128 three-digit natural numbers that are divisible by

1Thank You

Yogita Ingle 5 years ago

Three digit numbers divisible by 7 are

<div>

105, 112, 119, ..., 994

This is an AP with first term (a) = 105 and common difference (d) = 7

Let an be the last term.

an = a + (n - 1)d

994 = 105 + (n - 1)(7)

7(n - 1) = 889

n - 1 = 127

n = 128

Thus, there are 128 three-digit natural numbers that are divisible by 7.

</div>

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