No products in the cart.

Construct a grouped frequency distribution table …

CBSE, JEE, NEET, CUET

CBSE, JEE, NEET, CUET

Question Bank, Mock Tests, Exam Papers

NCERT Solutions, Sample Papers, Notes, Videos

Construct a grouped frequency distribution table taking class width equal to 20 in such a way that the mid-value of first class in 70.
  • 1 answers

Gaurav Seth 3 years, 11 months ago

Here , class width = 20
class mark = 70
Half of the class width =20 /2  =10
Upper limit of first class interval = 70 + 10 = 80
Lower limit of  first class interval = 70 – 10 = 60
Thus, class interval becomes 60 – 80
So, frequency distribution table becomes :

(a) Number of oranges weights more than 180 g = 1 + 1 = 2
(b) Number of oranges weights less than 100 g = 3 + 10 = 13 

http://mycbseguide.com/examin8/

Related Questions

2x+5y
  • 0 answers
X³-12x²+39x-28
  • 0 answers
What is 38747484±393884747
  • 0 answers
Ch-1 introduction
  • 0 answers
3√2×4√2×12√32
  • 0 answers

myCBSEguide App

myCBSEguide

Trusted by 1 Crore+ Students

Test Generator

Test Generator

Create papers online. It's FREE.

CUET Mock Tests

CUET Mock Tests

75,000+ questions to practice only on myCBSEguide app

Download myCBSEguide App