Solution : Given a triangle ABC, …

Solution : Given a triangle ABC, we are required to construct another triangle whosesides are 34 of the corresponding sides of the triangle ABC.Steps of Construction :1.Draw any ray BX making an acute anglewith BC on the side opposite to the vertexA.2.Locate 4 (the greater of 3 and 4 in 34)points B1, B2, B3 and B4 on BX so thatBB1 = B1B2 = B2B3 = B3B4.3.Join B4C and draw a line through B3 (the3rd point, 3 being smaller of 3 and 4 in34) parallel to B4C to intersect BC at C¢.4.Draw a line through C¢ parallelto the line CA to intersect BA at A¢(see Fig. 11.3).Then, D A¢BC¢ is the required triangle.Let us now see how this construction gives the required triangle.By Construction 11.1, BC3CC1¢=×¢Therefore, BCBC+CCCC1411BCBCBC33¢¢¢==+=+=¢¢¢, i.e.,BCBC¢ = 34.Also C¢A¢ is parallel to CA. Therefore, D A¢BC¢ ~ D ABC.(Why ?)So,ABACBC3ABACBC4¢¢¢¢===×

Is it possible to design a rectangular mango Grove whose length is twice it's breadth, and the area is 800m²? If so, find it's length and breadth

Find the nature of quadratic equation x^2 +x -5 =0

X-y=5

Prove that root 8 is an irration number

sin60° cos 30°+ cos60° sin 30°

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(A + B )²

Venu Gopal has twice

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If 1/2 is a root of equation x^2+kx- 5/4 =0 , then what is the value of k