Solution : Given a triangle ABC, …

CBSE, JEE, NEET, CUET
Question Bank, Mock Tests, Exam Papers
NCERT Solutions, Sample Papers, Notes, Videos
Solution : Given a triangle ABC, we are required to construct another triangle whosesides are 34 of the corresponding sides of the triangle ABC.Steps of Construction :1.Draw any ray BX making an acute anglewith BC on the side opposite to the vertexA.2.Locate 4 (the greater of 3 and 4 in 34)points B1, B2, B3 and B4 on BX so thatBB1 = B1B2 = B2B3 = B3B4.3.Join B4C and draw a line through B3 (the3rd point, 3 being smaller of 3 and 4 in34) parallel to B4C to intersect BC at C¢.4.Draw a line through C¢ parallelto the line CA to intersect BA at A¢(see Fig. 11.3).Then, D A¢BC¢ is the required triangle.Let us now see how this construction gives the required triangle.By Construction 11.1, BC3CC1¢=×¢Therefore, BCBC+CCCC1411BCBCBC33¢¢¢==+=+=¢¢¢, i.e.,BCBC¢ = 34.Also C¢A¢ is parallel to CA. Therefore, D A¢BC¢ ~ D ABC.(Why ?)So,ABACBC3ABACBC4¢¢¢¢===×
Posted by Rishabh Pawar 5 years ago
- 0 answers
ANSWER
Related Questions
Posted by Parinith Gowda Ms 2 months, 2 weeks ago
- 0 answers
Posted by Parinith Gowda Ms 2 months, 2 weeks ago
- 1 answers
Posted by Vanshika Bhatnagar 1 year, 3 months ago
- 2 answers
Posted by Kanika . 4 days, 4 hours ago
- 1 answers
Posted by Hari Anand 5 months, 1 week ago
- 0 answers
Posted by Sahil Sahil 1 year, 3 months ago
- 2 answers

myCBSEguide
Trusted by 1 Crore+ Students

Test Generator
Create papers online. It's FREE.

CUET Mock Tests
75,000+ questions to practice only on myCBSEguide app
myCBSEguide