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Solution : We havex2 + 7x …

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Solution : We havex2 + 7x + 10 = (x + 2)(x + 5)So, the value of x2 + 7x + 10 is zero when x + 2 = 0 or x + 5 = 0, i.e., when x = – 2 orx = –5. Therefore, the zeroes of x2 + 7x + 10 are – 2 and – 5. Now,sum of zeroes =2(7)–(Coefficientof),–2(–5)–(7)1Coefficientofxx-+===product of zeroes =210Constantterm(2)(5)101Coefficientofx

Posted by Rishabh Pawar 5 years ago

CBSE > Class 10 > Mathematics

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CBSE > Class 10 > Mathematics