Find the area of quadrilateral ABCD …

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Yogita Ingle 5 years, 2 months ago
Area of Quadrilateral = ar of ∆ABC + ar of ∆ADC
(s%20-%20b)(s%20-%20c)%7D%20%5C%5C)

(s%20-%20b)(s%20-%20c)%7D%20%5C%5C%20%3D%20%5Csqrt%7B6(6%20-%203)(6%20-%204)(6%20-%205)%7D%20%5C%5C%20%3D%20%5Csqrt%7B6%20%5Ctimes%203%20%5Ctimes%202%20%5Ctimes%201%20%7D%20%5C%3A%20%7Bcm%7D%5E%7B2%7D%20%5C%5C%20%3D%20%5Csqrt%7B6%20%5Ctimes%206%7D%20%5C%3A%20%7Bcm%7D%5E%7B2%7D%20%5C%5C%20%3D%206%20%7Bcm%7D%5E%7B2%7D)
(s%20-%20b)(s%20-%20c)%7D%20%5C%5C%20%5C%3A%20s%20%3D%20%5Cfrac%7Ba%20%2B%20b%20%2B%20c%7D%7B2%7D%20%5C%5C%20%5Cfrac%7B5%20%2B%204%20%2B%205%7D%7B2%7D%20%3D%20%5Cfrac%7B14%7D%7B2%7D%20%3D%207cm%20%5C%5C%20%5C%5C%20ar%20%5C%3A%20of%20%5C%3A%20triangle%20%5C%3A%20%5C%5C%20%3D%20%5Csqrt%7B7(7%20-%205)(7%20-%204)(7%20-%205)%7D%20%5C%5C%20%3D%20%5Csqrt%7B7%20%5Ctimes%202%20%5Ctimes%203%20%5Ctimes%202%7D%20%5C%5C%20%3D%20%5Csqrt%7B2%20%5Ctimes%202%20%5Ctimes%207%20%5Ctimes%203%7D%20%5C%5C%20%3D%202%5Csqrt%7B21%7D%20%5C%5C%20%3D%202%20%5Ctimes%204.58%20%3D%209.16%20%7Bcm%7D%5E%7B2%7D)
)
Area of ∆ABC ::•• •●
heron's formula
{where, s is semi perimeter}
area of ∆ABC
Area of∆ADC ::•• •●
Area of Quadrilateral = ar of ∆ABC + ar of ∆ADC
So the Area of Quadrilateral ABCD = 15.2cm .sq
0Thank You