No products in the cart.

Find cosec30° and cos60° geometrically

CBSE, JEE, NEET, CUET

CBSE, JEE, NEET, CUET

Question Bank, Mock Tests, Exam Papers

NCERT Solutions, Sample Papers, Notes, Videos

Find cosec30° and cos60° geometrically
  • 2 answers

Sia ? 5 years, 8 months ago


Let a triangle ABC with each side equal to 2a
{tex}\angle{/tex}A = {tex}\angle{/tex}B = {tex}\angle{/tex}C = 60°
Draw AD perpendicular to BC
In {tex}\triangle{/tex}BDA and {tex}\triangle{/tex}CDA
AB = AC, AD = AD and {tex}\angle BDA=\angle CDA{/tex}
{tex}\triangle B D A \cong \triangle C D A{/tex} by RHS
BD = CD
{tex}\angle{/tex}BAD = {tex}\angle{/tex}CAD = 30° by CPCT
In {tex}\triangle{/tex}BDA, {tex}\text{cosec} 30 ^ { \circ } =\frac HP= \frac { A B } { B D } = \frac { 2 a } { a } = 2{/tex} and {tex}\cos 60 ^ { \circ } =\frac BH= \frac { B D } { A B } = \frac { a } { 2 a } = \frac { 1 } { 2 }{/tex}

Unknown Man 2 years, 4 months ago

let a triangle ABC with each side equal to 2a /_
http://mycbseguide.com/examin8/

Related Questions

(A + B )²
  • 1 answers
Venu Gopal has twice
  • 0 answers
X-y=5
  • 1 answers
Find the nature of quadratic equation x^2 +x -5 =0
  • 0 answers
sin60° cos 30°+ cos60° sin 30°
  • 2 answers

myCBSEguide App

myCBSEguide

Trusted by 1 Crore+ Students

Test Generator

Test Generator

Create papers online. It's FREE.

CUET Mock Tests

CUET Mock Tests

75,000+ questions to practice only on myCBSEguide app

Download myCBSEguide App