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A vertical pole of 6m high …

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A vertical pole of 6m high casts a shadow 4m long on the ground . At the same time a tower casts a shadow 28m long .Find the height of the tower.

Posted by ?Isha .B 4 years, 10 months ago

CBSE > Class 10 > Mathematics

4 answers

Xyz Student 4 years, 10 months ago

Solution: Given AB=6 cm, BC=4 m, QR=28 m. To find:PQ. In ∆ABC and ∆PQR. Angle B= Angle Q= 90°[ Vertical]. Angle ACB= Angle PRQ [same angle on both, from sum]. By AA Criterion ∆ABC ∆PQR Corresponding sides of similar triangles are in proportion AB/PQ = BC/QR = 6/PQ = 4/28. PQ = (28*6)/4 = 42 cm. Height of tower = 42m

1Thank You

?Isha .B 4 years, 10 months ago

Please...Explain... The Method...

0Thank You

Atul Kumar 4 years, 10 months ago

42meter

1Thank You

Akhya Sahay 4 years, 10 months ago

42 m

3Thank You

ANSWER

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