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Sum of first n even natural …

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Sum of first n even natural numbers=n(n+1)
  • 1 answers

Khushi Singh 5 years ago

AP: ,2,4,6.... To n term a=2,d=2,n=n,sn=n(n+1) Sn=n÷2[2a+(n-1)d] n(n+1)=n÷2[2×2+2n-2] n(2n+2)=n(2n+2) Both sides are same. So, his answer is 0
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