. A tent is in the …

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Gaurav Seth 5 years, 1 month ago
Let r m be the radius and l m be the slant height of the cone, then

r = 2 m, and l = 2.8 m
Let r1 m be the radius and h m be the height of the cylinder, then
Now, r1 – 2 m and h = 2.1 m
Area of the canvas used
= CSA of cone + CSA of cylinder
= πrl + 2 πr1h
= πrl + 2πrh [r = r1]
= π r (l + 2h) m2
and Cost of canvas of the tent
= Rs. (500 x 44)
= Rs. 22,000.
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