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Sides of a triangle are in …

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Sides of a triangle are in the ratio of12:17:25 and its perimeter is 540cm. Find its area
  • 2 answers
P=540cm. Sides=12x+17x+25x Perimeter=Sum of all sides. 540=54x x=10 Sides of triangle;120cm, 170cm, 250cm. Area of triangle =s√s(s-a) (s-b) (s-c) s=540÷2=270 s-a=270-120=150 s-b=270-170=100 s-c=270-250=20 √270×150×100×20 √81,000,000 9000cm²

Yogita Ingle 4 years ago

Ratio of the sides of the triangle = 12 : 17 : 25
Let the common ratio be x then sides are 12x, 17x and 25x
Perimeter of the triangle = 540cm
12x + 17x + 25x = 540 cm
⇒ 54x = 540cm
⇒ x = 10
Sides of triangle are,
12x = 12 × 10 = 120cm
17x = 17 × 10 = 170cm
25x = 25 × 10 = 250cm
Semi perimeter of triangle(s) = 540/2 = 270cm
Using heron's formula,Area of the triangle = √s (s-a) (s-b) (s-c)                                       

= √270(270 - 120) (270 - 170) (270 - 250)cm2                                       
= √270 × 150 × 100 × 20 cm2                                       

= 9000 cm2

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