Determine whether the given quadratic equation …

CBSE, JEE, NEET, CUET
Question Bank, Mock Tests, Exam Papers
NCERT Solutions, Sample Papers, Notes, Videos
Posted by Ok Wahsi 5 years, 1 month ago
- 1 answers
Related Questions
Posted by Vanshika Bhatnagar 1 year, 3 months ago
- 2 answers
Posted by Hari Anand 5 months, 1 week ago
- 0 answers
Posted by Kanika . 4 days, 11 hours ago
- 1 answers
Posted by Sahil Sahil 1 year, 3 months ago
- 2 answers
Posted by Parinith Gowda Ms 2 months, 2 weeks ago
- 0 answers
Posted by Parinith Gowda Ms 2 months, 2 weeks ago
- 1 answers

myCBSEguide
Trusted by 1 Crore+ Students

Test Generator
Create papers online. It's FREE.

CUET Mock Tests
75,000+ questions to practice only on myCBSEguide app
myCBSEguide
Gaurav Seth 5 years, 1 month ago
We have been given, x2 - 2x + 1 = 0
Now we also know that for an equation ax2 + bx + c = 0, the discriminant is given by the following equation:
D = b2 - 4ac
Now, according to the equation given to us, we have,a = 1, b = -2 and c = 1.
Therefore, the discriminant is given as,
D = (-2)2 - 4(1)(1)
= 4 - 4
= 0
Since, in order for a quadratic equation to have real roots, D ≥ 0.Here we find that the equation satisfies this condition, hence it has real and equal roots.
Now, the roots of an equation is given by the following equation,
x=-b± underroot D / 2a
Therefore, the roots of the equation are given as follows,
x=-(-2)±0 / 2(1)
=2 / 2
= 1
Therefore, the roots of the equation are real and equal and its value is 1.
0Thank You