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Given the HCF (306, 657) = …

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Given the HCF (306, 657) = 9, find LCM (306, 657)

Posted by Om Shukla 5 years, 1 month ago

CBSE > Class 10 > Mathematics

2 answers

Parul Ailawadi 5 years, 1 month ago

LCM×HCF=Product of two numbers LCM×9=306×657 LCM×9=201042 LCM=201042÷9 LCM=22338

Anuj Mathpal 5 years, 1 month ago

Let the LCM = x. HCF *LCM =Product of two numbers. 9*x=306*657 x=306*657/9 x=34*657 x=22,338

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