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On dividing x^3-3x^2+x+2 by a polynomial …

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On dividing x^3-3x^2+x+2 by a polynomial g(x), the quotient and remainder were x-2 and-2x+4 respectively. Find g(x).
  • 2 answers

Rîtíkã Çhäûhāñ 5 years, 1 month ago

Dividend =p(x)=x 3 −3x 2 +x+2 Quotient =q(x)=x−2 Remainder =r(x)=2x+4 By division algorithm, p(x)=q(x)g(x)+r(x) ⇒g(x)= q(x) p(x)−r(x) ​ ⇒g(x)= x−2 x 3 −3x 2 +x+2+2x−4 ​ ⇒g(x)= x−2 x 3 −3x 2 +3x−2 ​ So, g(x)=x 2 −x+1 solution

Gaurav Seth 5 years, 1 month ago

Answer:

g(x) = x² - x + 1

Step-by-step explanation:

On dividing x3-3x2+x+2 by a polynomial g(x),the quotient and remainder were x-2 and -2x+4 respectively.find g(x)

 

f(x) = x³ - 3x² + x + 2

q(x) = x - 2

let say

g(x) = ax² + bx + c

r = - 2x + 4

f(x)  = g(x)q(x) + r

=> x³ - 3x² + x + 2 = (ax² + bx + c)(x - 2) + (-2x + 4)

=> x³ - 3x² + x + 2 =  ax³ + x²(b - 2a) + x(c - 2b) -2c -2x + 4

=> x³ - 3x² + x + 2 =  ax³ + x²(b - 2a) + x(c - 2b - 2)  + (-2c  + 4)

Equating Power terms

a = 1

b - 2a = - 3  => b -2 = -3 => b = -1

c - 2b - 2 = 1 => c + 2 - 2 = 1  => c = 1

or -2c  + 4 = 2  => -2c = -2 => c = 1

 

g(x) = x² - x + 1

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