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How many terms are there in the sequence 3,6,9,.....111?

Posted by Tanveer Kaur 5 years, 1 month ago

CBSE > Class 10 > Mathematics

1 answers

Yogita Ingle 5 years, 1 month ago

The given sequence is an A.P. with first term a=3 and common difference d=3. Let there be n terms in the given sequence. Then,

n^th term=111

a+(n−1)d=111

3+(n−1)×3=111

n=37

Thus, the given sequence contains 37 terms.

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