in triangle abc if angle b …
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Gaurav Seth 3 years, 11 months ago
It is given that
∠B = 35°
∠C = 65°
AP is the bisector of ∠CAB
We have to arrange AP, BPand CP in descending order.
In ΔACP we have
∠ACP = 65°
∠CAP = 40°(As AP is the bisector of ∠CAB
So AP > CP (Sides in front or greater angle will be greater) ........(1)
In ΔABP we have
∠BAP = 40°(As AP is the bisector of ∠CAB)
Since,
∠BAP >∠ABP
So BP > AP ..........(2)
Hence
From (1) & (2) we have
BP > AP > CP
0Thank You